123456789101112131415161718192021222324import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); public ..
알고리즘 풀이/SWEA
123456789101112131415161718192021222324import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); public ..
12345678910111213141516171819202122232425import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter;import java.util.StringTokenizer; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new Outpu..
12345678910111213141516171819202122import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter; public class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); publ..
123456789101112131415161718192021222324import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter;import java.util.StringTokenizer; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new OutputS..
말이 2마리인 경우는 늦게 도착하는 말만 생각해서 문제를 해결하면 된다 결국 가장 늦게 도착하는 말과 문제에서 요구하는 xkm/h의 속력으로 이동하는 크루즈가 종로까지 동시에 도착할 때의 x값을 구해주면 되는 문제임 소수점때문에 거리도 double형으로 통일해주고 변수D의 값 10^9까지 double이 허용해주나 안해주나 헷갈려서 한번 넣어봤는데 한번에 됏음 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 import java.io.BufferedReader; import java.io.BufferedWriter; im..
1234567891011121314151617181920212223import java.io.BufferedReader;import java.io.BufferedWriter;import java.io.IOException;import java.io.InputStreamReader;import java.io.OutputStreamWriter; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); private static BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(System.out)); public st..
StringBuilder 인스턴스를 그대로 넣어준 것과 StringBuilder의 toString()함수를 붙여준 것과의 차이점은 무엇인가요? There's nothing different between line 6 and line 8. PrintStream.println(Object) calls string.valueOf(Object) which calls the object's toString() method, and that gets printed. System.out.println(s) and System.out.println(s.toString()) have the same output (unless s is null, in which case the latter throws an excepti..
StringBuilder replace로 하려고 했는데 함수가 없음 String.replace로 해결 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; class Solution { private static BufferedReader br = new BufferedReader(new InputStreamReader(Syste..
split함수를 공백을 기준으로 쪼갰을 때 공백이 2연속되는 경우에는 공백 사이의 null값을 배열의 요소로 정의한다는 것을 알게 되었다 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; class Solution { private static BufferedReader br = new BufferedReader(n..
